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Given : Fe^(2+)(aq)+2e^(-) rarr Fe(s),...

Given `:`
`Fe^(2+)(aq)+2e^(-) rarr Fe(s), " "E^(c-)=-0.44V`
`Al^(3)+3e^(-) rarr Al(s)," "E^(c-)=-1.66V`
`Br^(2+)+2e^(-)rarr 2Br^(c-)(aq)" "E^(c-)=-1.08V`
The decreasing order of reducing power is `………………………………..` .

Text Solution

Verified by Experts

The correct Answer is:
`(Al>Fe>Br^(c-))`
`(AlgtFegtBr^(c-))`
More the oxidation potential, more the reducing power.
`:. E^(c-)._(o x i d (Al|Al^(3+))(+1.66C))gtE^(c-)._( o x i d(Fe|Fe^(2+)))(0.044V)gt`
`E^(c-)._(o x i d(2Br^(c-)|Br_(2)))(-1.08V)`
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