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A current of 2A is passed for 1.93 xx 10...

A current of `2A` is passed for `1.93 xx 10^(4)s ` through a molten tin salt depositing `23.8 g Sn (Aw` of `Sn=119)`. The oxidation state of `Sn` in the salt is `…………………………`.

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The correct Answer is:
`(+2)`
`(+2)`
Mole of `Sn` deposited `=(23.8)/(119)=0.2mol`
Number of Faradays `=(2xx1.93xx10^(4))/(96500)=0.4F`
Oxidation state of `Sn=().4)/(0.2)=2`
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