`AgNO_(2)(aq)` was added to an aqueous `KCl` solution gradually and the conductivity of the solution was measured. The plot conductivity of the solution was measured. The plot of conductance `(wedge)` versus the volume of `AgNO_(3)` is

Options

A. `P`
B. `Q`
C. `R`
D. `S`

Answer

d

Explanation

`AgNO_(3)(aq)+KCl(aq) rarr AgCldarr+KNO_(3)(aq)`
In this reaction, `Cl^(c-)` ions are relaced by `NO_(3)^(c-)` ions.
`i.` Till all `KCl(Cl^(c-)` ions `)` gets consumed by `NO_(3)^(c-)` ions, `Cl^(c-)` will get replaced by `NO_(3)^(c-)` ion.
`K^(o+)Cl^(c-) overset(AgNO_(3))rarrK^(o+)NO_(3)^(c-)`.
Conductance is constant since the conductance `(wedge)` of `Cl^(c-)~~` conductance of `NO_(3)^(c-)`.
Initially, conductance do not fall of to a large extent. Even the fall `//` rise will be linear `(` either decreasing or increasing `)`.
`ii.` When all `Cl^(c-)` ions are reacted and no reaction occurs, there are `Ag^(o+), NO_(3)^(c-)`, and `K^(o+)` ions are left in the solution which increases the conductance of solution sharply.
`K^(o+)Cl^(c-) overset(AgNO_(3))rarr Ag^(o+)+K^(o+)+NO_(3)^(c-)`
Hence, graph`(s)` is the most appropriate answer.