How long a current of `3A` has to be passed through a solution of silver nitrate to coat a metal surface of `80cm^(2)` with a `0.005-mm-` thick layer ? The density of silver is `10.5g cm^(-3)`.

Answer

`125.09s`

Explanation

Volume of the surface `(V)=` Area `xx` Thickness
Given,
Area `=80cm^(2),` thickness `=0.005mm=0.00005cm`
Mass of `Ag(W)=Vxx` Density
`=0.04xx10.5=0.42g`
`Ag^(o+)+e^(-) rarr Ag`
`:. W_(Ag)=(Zit)/(96500)`
`0.42=(108xx3xxt)/(96500)`
`:. t=(0.42xx96500)/(108xx3)=(40530)?(324)=125.90s`