From the rate laws for the reactions given below, determine order with order to each species and the overall order:
(a) `2HCrO_(4)^(ɵ) + 6l^(ɵ) + 14H^(o+) rarr 2Cr^(3+) + 3I_(2) + 8H_(2)O`
Rate `= k[HCrO_(4)^(ɵ) ][I^(ɵ) ]^(2) [H^(o+)]^(2)`
(b) `H_(2)O_(2) + 2I^(ɵ) +2H^(o+) rarr I_(2)+2H_(2)O`
Rate `= k[H_(2)O_(2)] [I^(ɵ) ]`

Explanation

(a) The rofer of the reaction with respect to `[HCrO_(4)^(ɵ)]` is `1`, with respect to `[I^(ɵ)]` is `2`, and with respect to `[H^(o+)]` is `2`. The overall order of the reaction is `1 + 2 + 2 = 5`.
(b) The order of the reapect with respect to `[H_(2)O_(2)]` is `1` and with respect to `[I^(ɵ)]` is `1`. The overall order of the reaction is `1 + 1 = 2`.