For a reaction `3A rarr` Products, it is found that the rate of reaction doubles. If the concentration of `A` is increased four times, calculated the order of reaction.

Explanation

Rate`= k["Reactant"]^(n)`, if `["Reactant"] = a`, rate `= r_(1)`
`r_(1) = k[a]^(n)` , if `["Reactant"] = 4a, rate = 2r_(1)`
`2e_(1) = k[4a]^(n)`
`(1)/(2) = [(1)/(4)]^(n) rArr n = (1)/(2)`