Home
Class 12
CHEMISTRY
2N(2)O(5) rarr 4NO(2) + O(2) If (-d[N(...

`2N_(2)O_(5) rarr 4NO_(2) + O_(2)`
If `(-d[N_(2)O_(5)])/(dt) = k_(1)[N_(2)O_(5)]`
`(d[NO_(2)])/(dt) = k_(2)[N_(2)O_(5)]`
`(d[O_(2)])/(dt) = k_(3)[N_(2)O_(5)]`
What is the relation between `k_(1), k_(2)`, and `k_(3)`?

Text Solution

Verified by Experts

`(-d[N_(2)O_(5)])/(2 dt) = (d[NO_(2)])/(4 dt) = (-d[O_(2)])/(dt)`
`(k_(1)[N_(2)O_(5)])/(2) = (k_(2)[N_(2)O_(5)])/(4) = (k_(3)[N_(2)O_(5)])/(1)`
Multiply by `4`, we get
`2k_(1) = k_(2) = 4k_(3)`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY|Exercise Solved Example|52 Videos

  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY|Exercise Ex 4.1 (Objective)|9 Videos

  • CARBOXYLIC ACIDS AND THEIR DERIVATIVES

    CENGAGE CHEMISTRY|Exercise Exercises Archives (Analytical And Descriptive)|34 Videos

  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Archives Subjective|18 Videos

Similar Questions

Explore conceptually related problems

For the reaction, N_(2)O_(5) rarr 2NO_(2)+1/2O_(2), Given -(d[N_(2)O_(5)])/(dt)=K_(1)[NO_(2)O_(5)] (d[NO_(2)])/(dt)=K_(2)[N_(2)O_(5)] and (d[O_(2)])/(dt)=K_(3)[N_(2)O_(5)] The relation in between K_(1), K_(2) and K_(3) is:

The rate of reaction. 2N_(2)O_(5) to 4NO_(2) + O_(2) can be written in three ways. (-d[N_(2)O_(5)])/(dt) = k[N_(2)O_(5)] (d[N_(2)O_(5)])/(dt) =( k^(')[N_(2)O_(5)]) (d[O_(2)])/(dt) = (k^(')[N_(2)O_(5)]) The relation between k and k^(') are:

2N_2O_5 rarr 4 NO_2 +O_2 If -(D[N_2O_5])/(dt) =k_1[N_2O_5] (d[NO_2])/(dt) =k_2[N_2O_5] ([O_2])/(dt) =k_3[N_2O_5] What is the relation between k_1, k_2 and k_3 ? .

Consider the following reaction, 2N_(2)O_(5)rarr4NO_(2)+O_(2),(d[NO_(2)] )/(dt)=k_(2)[N_(2)O_(5)] , (d[O_(2)])/(dt)=k_(3)[N_(2)O_(5)]" and "(d)/(dt)[N_(2)O_(5)]=k_(1) The relation between k_(1), k_(2) and k_(3) is

CENGAGE CHEMISTRY-CHEMICAL KINETICS-Archives Subjective
  1. 2N(2)O(5) rarr 4NO(2) + O(2) If (-d[N(2)O(5)])/(dt) = k(1)[N(2)O(5)]...

    Text Solution

    |

  2. Rate of a reaction A + B rarr Product, is given as a function of diffe...

    Text Solution

    |

  3. A first order reaction is 20% complete in 10 min. Calculate (a) the sp...

    Text Solution

    |

  4. While studying the decompoistion of gaseous N(2)O(5), it is observed t...

    Text Solution

    |

  5. A first order gas reaction has k = 1.5 xx 10^(-6) s^(-1) at 200^(@)C. ...

    Text Solution

    |

  6. A first order reaction is 50% completed in 30 min at 27^(@)C and in 10...

    Text Solution

    |

  7. In a Arrhenius equation for a certain reaction, the values of A and E(...

    Text Solution

    |

  8. The decomposition of N(2)O(5) according to the equation: 2N(2)O(5)(g) ...

    Text Solution

    |

  9. Two reaction, (I)A rarr Products and (II) B rarr Products, follow firs...

    Text Solution

    |

  10. The gas phase decomposition of dimethyl ether follows first order kine...

    Text Solution

    |

  11. A first order reaction A rarr B requires activation energy of 70 kJ mo...

    Text Solution

    |

  12. form the following data for the reaction between A and B, (a) Cal...

    Text Solution

    |

  13. At 380^(@)C , the half-life periof for the first order decompoistion o...

    Text Solution

    |

  14. The ionization constant of overset(o+)(NH(4)) ion in water is 5.6 xx 1...

    Text Solution

    |

  15. The time required for 10% completion of a first order reaction at 298 ...

    Text Solution

    |

  16. The rate constant for the first order decompoistion of a certain react...

    Text Solution

    |

  17. For the equation N(2)O(5)(g)=2NO(2)(g)+(1//2)O(2)(g), calculate the ...

    Text Solution

    |

  18. The rate constant of a reaction is 1.5 xx 10^(7)s^(-1) at 50^(@)C and ...

    Text Solution

    |

  19. The rate constant for an isomerization reaction, A rarr B is 4.5 xx 10...

    Text Solution

    |

  20. A hydrogenation reaction is carried out at 500 K. If the same reaction...

    Text Solution

    |

  21. The vapour pressure of two miscible liquids (A) and (B) are 300 and 50...

    Text Solution

    |