The rate of a gaseous reaction is given by the expresison `k[A]^(2)[B]^(3)`. The volume of the reaction vessel is suddenly reduced to one-half of the initial volume. The reaction rate relative to the original rate will be

Options

A. (a) `1//24`
B. (b) `1//32`
C. ( c) `32`
D. (d) `24`

Answer

C

Explanation

(c ) Rate `= k[A]^(2)[B]^(3)`
When the volume is halved, the concentration will become double.
`:.` Rate `= k[2A]^(2)[2B]^(3)`
`= 32k[A]^(2)[B]^(3)`
`= 32 xx` Original rate form Eq. (i).