At a certain temperature the half change periof for the catalystic decompoistion of ammonia was found as follows:
`|{:("Pressure (Pa)",6667,13333,26666),("Half life periof in hours",3.52,1.92,1.0):}|`
Calculate the order of reaction.

Explanation

`((t_(1//2))_(1))/((t_(1//2))_(2)) = ((a_(2))/(a_(1)))^(n-1)` (where `n` is order of reaction)
form the given data.
`(3.52)/(1.92) = ((13333)/(6667))^(n-1)` (`a prop` initial pressure)
`= (2)^(n-1)`
`log.(3.52)/(1.92) = (n-1)log2`
`= 0.310 xx (n-1)`
`0.2632 = 0.3010 xx (n-1)`
`n = 1.87 ~~ 2`
ismilar calculation are made between first and third observations. `n` comes equal to `1.908 (~~2)`.
Thus, the reaction is second order.