Pseudo first order rate for the reaction
`A + B rarr P`
when studied in `0.1 M` of `B` is given by
`-(d[A])/(dt) = -k[A]`
where `k = 1.85 xx 10^(4)s^(-1)`. Calculate the value of second order rate constant.

Explanation

`A + B rarr P`
`-(d[A])/(dt) = k[A]`
`-(d[A])/(dt) = 1.85 xx 10^(4) xx[A]`
Assuming the reaction to be of second order,
`-(d[A])/(dt) = k'[A][B]`
`-(d[A])/(dt) = k'[A][0.1]`
Dividing Eq. (i) by Eq. (ii), we get
`1 = (1.85 xx 10^(4))/(k'[0.1])`
`k' = 1.85 xx 10^(5)L mol^(-1) s^(-1)`