The number of flashes of firely change with temperature is as follows:
`|{:(T^(@)C,"Number of flashes/min",T^(@)C,"Number of flashes/min"),(25,7,38,47),(28,10,42,82),(32,20,44,108),(35,31,-,-):}|`
Determine the energy of activation for the chemical reaction that leads to the flsah. `(R= 8.314 Jmol^(-1)K^(-1))`

Explanation

`k_(1)= 7 min^(-1)`,when `T_(1)= 298K`
`k_(2)= 10 min^(-1)`, when `T_(2)= 301K`
`log.(k_(2))/(k_(1))=(E_(a))/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]`
`log.(10)/(7)=(E_(a))/(2.303Rxx8.314)xx[(301-298)/(301xx298)]`
`:. E_(a)= 88.678KJ mol^(-1)`