The rate constant, activation energy, and Arrphenius parameter of a chemical reaction are `3.0xx10^(-4)s^(-1), 104.4KJ mol^(-1)`, and `6.0xx10^(14)s^(-1)`, respectively. The value of rate constant as `Trarroo` is

Options

A. `2.0xx10^(18)s^(-1)`
B. `6.0xx10^(14)s^(-1)`
C. `3.6xx10^(30)s^(-1)`
D. None of these

Answer

B

Explanation

Given `k= 3.0xx10^(-4)s^(-1), A= 6.0xx10^(14)s^(-1)`
`E_(a)=104.4KJ mol^(-1)`
Arrhenius equation is
`k=Ae^(-E_(a)//RT)`
as `Trarroo`
`k=Ae^(-E_(a)//Rxxoo)oare^(0) [:.(-E_(a))/(Rxxoo)=0]`
or `k=A`
`:. k = 60 xx10^(14)s^(-1)` as `Trarroo`