Calculate the activation energy of a reaction whose reaction rate at `300 K` double for `10 K` rise in temperature.

Explanation

To calculate the activation energy (Ea) of a reaction whose rate doubles when the temperature increases by 10 K, we can use the Arrhenius equation and the relationship between the rate constants and temperature. Here’s a step-by-step solution:

### Step 1: Identify the given data
- Initial temperature, T1 = 300 K
- Final temperature, T2 = T1 + 10 K = 310 K
- The rate constant at T1 is k1, and at T2 is k2 = 2 * k1 (since the rate doubles).

### Step 2: Write the Arrhenius equation in logarithmic form
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