Home
Class 12
CHEMISTRY
In the presence of a catalyst, the rate ...

In the presence of a catalyst, the rate of a reaction grows to the extent of `10^(5)` times at `298 K`. Hence, the catalyst must have lowered `E_(a)` by

A

`25 kJ mol^(-1)`

B

`20 kJ mol^(-1)`

C

`10 kJ mol^(-1)`

D

`28.5 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(k_(cat))/(k) = "antilog"((Delta E_(a))/(2.303 RT))`
`log.(k_(cat))/(k) = (DeltaE_(a))/(2.303 RT)`
`log 10^(5) = (Delta E_(a))/(2.303xx8.314xx 10^(3)xx 298)`
`Delta E_(a) = 5 xx 2.303 xx 8.314 xx 298 xx 10^(-3)`
`= 28.53 kJ mol^(-1)`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY|Exercise Exercises Linked Comprehension|59 Videos

  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY|Exercise Exercises Multiple Correct|34 Videos

  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY|Exercise Ex 4.3 More Than One Correct|5 Videos

  • CARBOXYLIC ACIDS AND THEIR DERIVATIVES

    CENGAGE CHEMISTRY|Exercise Exercises Archives (Analytical And Descriptive)|34 Videos

  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Archives Subjective|18 Videos

Similar Questions

Explore conceptually related problems

In the presence of a catalyst, the activation energy is lowered by 3 Kcal at 27^(@) c .Hence the rate of reaction will increase by :

In presence of a catalyst, the activation energy is lowered by "2" kcal at \(127^{o}\)C .Hence, the rate as compared to the old rate is \(e^{x}\) times. then the value of "x" is

The activation energy of a reaction is 75.2 kJ mol^(-1) in the absence of a catalyst and 50.14 kJ mol^(-1) in the presence of a catalyst. How many times will the reaction grow in the presence of catalyst if the reaction proceeds at 25^(@) C ?

The activation energy of a first order reaction at 300 K is kJ mol^(-1) . In the presence of a catalyst, the activation energy gets lowered to 50kJ mol^(-1) at 300 K . How many times the reaction rate change in the presence of a catalyst at the same temperature ?