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ArarrB, DeltaH= -10 KJ mol^(-1), E(a(f))...

`ArarrB, DeltaH= -10 KJ mol^(-1), E_(a(f))=50 KJ mol^(-1)`, then `E_(a)` of `BrarrA` will be

A

`40 KJ mol^(-1)`

B

`50 KJ mol^(-1)`

C

`-50 KJ mol^(-1)`

D

`60 KJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`A rarr B, DeltaH = -10 KJ mol^(-1)`
It is an exothermic reaction.
`E_(a(b))=E_(a(f))-(DeltaH)`
`=50 -(-10)`
`=60 KJ`
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