Rate constant `k = 1.2 xx 10^(3) mol^(-1) L s^(-1)` and `E_(a) = 2.0 xx 10^(2) kJ mol^(-1)`. When `T rarr oo`:

Options

A. `A = 2.0 xx 10^(2) kJ mol^(-1)`
B. `A = 1.2 xx 10^(3) mol^(-1) L s^(-1)`
C. `A = 1.2 xx 10^(3) mol L^(-1) s^(-1)`
D. `A = 2.4 xx 10^(3) kJ mol^(-1) s^(-1)`

Answer

B

Explanation

`k=Ae^(-Ea//RT)`
if `Trarroo, k=A`