The rate constant of a reaction is `0.0693 min^(-1)`. Starting with `10 mol`, the rate of the reaction after `10 min` is

Options

A. `0.0693 mol min^(-1)`
B. `0.0693 xx 2 mol min^(-1)`
C. `0.0693 xx 5 mol min^(-1)`
D. `0.0693 xx (5)^(2) mol min^(-1)`

Answer

C

Explanation

`t_(1//2)=(0.693)/(k)=(0.693)/(0.0693)=10 min`
Reactant after `10 min = 5 mol`
`Rate ((dx)/(dt))=k[A]=0.0693xx5 mol min^(-1)`