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A catalyst lowers the activation energy ...

A catalyst lowers the activation energy of a reaction form `20 kJ mol^(-1)` to `kJ mol^(-1)`. The temperature at which the uncatalyzed reaction will have the same rate as that of the catalyzed at `27^(@)C` is

A

`-123^(@)C`

B

`327^(@)C`

C

`32.7^(@)C`

D

`+23^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B
`(E'_(a))/(T_(1)) = (E_(a))/(T_(2)) = (10)/(300) = (20)/(T_(2))`
`:. T_(2) = 600 K =327^(@)C`
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