In a certain reaction, `10%` of the reactant decomposes in one hour, `20%` in two hours, `30%` in theee hours, and so on. The dimenison of the velocity constant (rate constant) are

Options

A. `hr^(-1)`
B. `Mol L^(-1) hr^(-1)`
C. `L mol^(-1) s^(-1)`
D. `Mol s^(-1)`

Answer

B

Explanation

form the question, it is clear `t_(1//2) prop a`. Hence, zero order reaction. So, dimenison of `k = mol L^(-1) hr^(-1)`.
For zero order: `t = (x)/(k) or k = (x)/(t)`
If `t = t_(10%) = 10 min, x = 10`,
Then, `k = (10)/(10) = 1 mol L^(-1) t^(-1)`.
If `t = t_(20%) = 20 min, x = 20`,
Then, `k = (20)/(20) = 1 mol L^(-1) t^(-1)`.
ismilarly, for `30%` and so on. Thus, reaction is of zero order.