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The half life of decompoistion of N(2)O(...

The half life of decompoistion of `N_(2)O_(5)` is a first order reaction represented by `N_(2)O_(5)rarrN_(2)O_(4)+1//2O_(2)`
After `15`min the volume of `O_(2)` profuced is `9ml` and at the end of the reaction `35ml`. The rate constant is equal to

A

`(1)/(15)log_(e).(35)/(26)`

B

`(1)/(15)log_(e).(44)/(26)`

C

`(1)/(15) log_(e).(35)/(36)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`k = (2.303)/(t)log.(V_(oo))/(V_(oo)-V_(t))`
`= (1)/(t) log_(e).(V_(oo))/(V_(oo)-V_(t))`
`= (1)/(15)log_(e).(35mL)/((35-9)mL) = (1)/(15)log_(e).(35)/(26)`
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