`t_(1//2) =` constant confirms the first order of the reaction as one `a^(2)t_(1//2) =` constant confirms that the reaction is of

Options

A. Zero order
B. First order
C. Second order
D. Third order

Answer

D

Explanation

For `nth` ofer, `t_(1//2) prop (a)^(1-n)`.
`rArr (t_(1//2))/((a)^(1-n)) or t_(1//2) xx (a)^(n-1) = "Constant"`
Given `t_(1//2) xx (a)^(n-1) = t_(1//2)(a)^(2)`.
`rArr (a)^(n-1) = (a)^(2)`
`:. n-1 = 2 rArr n = 3`.
Hence, third order reaction.