The compoistion of `N_(2)O_(5)` is a first order reaction represented by: `N_(2)O_(5) rarr N_(2)O_(4) + 1//2O_(2)`.
After `20 min` the volume of `O_(2)` profuced is `10 mL` and at the end of the reaction `40 mL`. The rate constant is equal to

Options

A. `(1)/(20)ln.(30)/(50)`
B. `(1)/(20)ln.(50)/(30)`
C. `(1)/(20)ln.(50)/(40)`
D. `(1)/(20)ln.(40)/(30)`

Answer

D

Explanation

`k = (2.303)/(t)log.(V_(oo))/(V_(oo)-V_(t))`
or `k = (1)/(t)ln.(V_(oo))/(V_(oo)-V_(t))`
`k = (1)/(20) ln.(40)/((40-10))`
`= (1)/(20) ln.(40)/(30)`