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The slowest step of a particular reactio...

The slowest step of a particular reaction is found to be `1//2X_(2) + Y_(2) rarr XY_(2)`. The order of the reaction is

A

`2`

B

`3`

C

`3.5`

D

`1.5`

Text Solution

Verified by Experts

The correct Answer is:
D
Slow step is:
`(1)/(2)X_(2) + Y_(2) rarr XY_(2)`
Hence,
`r = k[X_(2)]^(1//2)[Y_(2)]`
`OR = (1)/(2)+1 = 1(1)/(2)`
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