The hydrolyiss of an ester was carried out with `0.1 M H_(2)SO_(4)` and `0.1 M HCl` separately. Which of the following expresison between the rate constants is expected ? The rate expresison being rate `= k[H^(o+)]["ester"]`

Options

A. `k_(HCl) = k_(H_(2)SO_(4))`
B. `k_(HCl) gt k_(H_(2)SO_(4))`
C. `k_(HCl) lt k_(H_(2)SO_(4))`
D. `k_(H_(2)SO_(4)) = 2k_(HCl)`

Answer

B

Explanation

`[H_(2)SO_(4)] = 0.1 M = 0.1 xx 2 = 0.2 N`
`[HCl] = 0.1 N`
In case of `H_(2)SO_(4)`
`r_(1) = k[H^(o+)]["Ester"]`
`k_(H_(2)SO_(4)] = (r_(1))/(2 N xx ["Ester"])`
In case of `HCl`,
`r_(2) = k[H^(o+)]["Ester"]`
`k_(HCl) = (r_(2))/(1 N xx ["Ester"])`
Hence `K_(HCl) gt K_(H_(2)SO_(4)`