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When the concentration of a reactant in ...

When the concentration of a reactant in reaction `A rarr B` is increased by `8` times but rate increases only `2` times, the order of the reaction would be

A

`2`

B

`1//3`

C

`4`

D

`1//2`

Text Solution

Verified by Experts

The correct Answer is:
B
`r_(1) = k[A]^(n)`
`r_(2) = 2r_(1) = k[8A]^(n)`
`:. (2r_(1))/(r_(1)) = (8)^(n)`
`(2)^(1) = (2)^(3n)`
`:. 3n = 1`
`n = (1)/(3)`
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