The rate of reaction between `A` and `B` increases by a factor of `100`, when the concentration with respect to `A` is increased `10` folds, the order of reaction w.r.t. `A` is

Options

A. `10`
B. `1`
C. `4`
D. `2`

Answer

D

Explanation

`r_(1) = k[A]^(n)`
`r_(2) = 100 r_(1) = k[10 A]^(n)`
`(100r_(1))/(r_(1)) = (10)^(n)`
`(10)^(2) = (10)^(n)`
`n = 2`