Diazonium salt decomposes as
`C_(6)H_(5)N_(2)^(o+)Cl^(ɵ) rarrC_(6)H_(5)Cl+N_(2)`
at `10^(@)C`, the evolution of `N_(2)` becomes two first faster when the initial concentration of the salt is doubled. Thus, it is

Options

A. A first order reaction
B. A second order reaction
C. Independent of the initial concentration of reactant
D. A zero order reaction.

Answer

A

Explanation

`r_(1) = k["salt"]^(n)`
`r_(2) = 2r_(1) = k[2 "salt"]^(n)`.
`(2r_(1))/(r_(1)) = (2)^(n)`
`(2)^(1) = (2)^(n)`
`n = 1`