At `27^(@)C` it was observed in the hydrogenation of a reaction, the pressure of `H_(2)(g)` decreases form `10 atm` to `2 atm` in `10 min`. Calculate the rate of reaction in `M min^(-1)` (Given `R = 0.08 L atm K^(-1) mol^(-1)`)

Options

A. `0.02`
B. `0.03`
C. `0.04`
D. `0.05`

Answer

B

Explanation

Rate `= ((10-2)atm)/(10 min) = 0.8 atm min^(-1)`
Rate in `M min^(-1)` is given by:
Rate `= (Delta (n//v))/(Delta t) M min^(-1) = (Delta P)/(Delta t) xx (1)/(RT)`
`= (0.8)/(0.08 xx 300)`
`= 0.03 M min^(-1)`