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Following is the graph between log t(1//...

Following is the graph between `log t_(1//2)` and `log a` (`a` initial concentration) for a given reaction at `27^(@)C`.

Find the order of reaction.

Text Solution

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The correct Answer is:
0
`t_(1//2) prop 1/a_(0)^(n-1)`
`t_(1//2)=k.1/a_(0)^(n-1)`
`log t_(1//2)=log k-(n-1) log a_(0), [y=c+mx]`
`tan 45^(@)=1`
`:. n=0`
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