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What is the order of reaction for which ...

What is the order of reaction for which rate becomes half if volume of the container having same amount of reactant is doubled? Assume gaseous phase reaction.

Text Solution

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The correct Answer is:
1
Rate `= k[a]^(n)`
Case I: `r_(1) = k[(a)/(V)]^(n)` …(i)
Case II: `(r_(1))/(2) = k[(a)/(2V)]^(n)` …(ii)
By Eqs. (i) and (ii).
`(2)^(1) = (2)^(n)`
`:. n = 1`
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