The rate constant, the activation energy, and the Arrhenius parameter of a chemical reaction at `25^(@)C` are `3.0xx10^(-4)S^(-1), 104.4 KJ mol^(-1)`, and `6.0xx10^(14)S^(-1)`, respectively. The value of the rate constant as `Trarroo` is

Options

A. `2.0 xx 10^(18)s^(-1)`
B. (b) `6.0 xx 10^(14) s^(-1)`
C. Infinity
D. `3.6 xx 10^(30) s^(-1)`

Answer

B

Explanation

`k = Ae^(-E_(a)//RT)`
As `T rarr oo, k = A = 6.04 xx 10^(14) s^(-1)`