For the reaction `N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g)`, uneder certain conditions of temperature and pressure of the reactants, the rate of formation, of ammonia is `0.001 kg hr ^(-1)`. The rate of consumption of hydrogen under the same conditions is ...... kg `hr^(-1)`

Answer

`1.765 xx 10^(-4) kg hr^(-1)`

Explanation

First methof
`(-d[H_(2)])/(dt) = (3)/(2)(d[NH_(3)])/(dt) xx (Mw of H_(2))/(Mw of NH_(3))`
`= (3)/(2) xx 0.001 kg hr^(-1) xx (2)/(17)`
`= 1.765 xx 10^(-4) kg hr^(-1)`
Seoncd methof
`3H_(2) -= 2NH_(3)`
`3 xx 2 -= 2 xx 17`
`(-d[H_(2)])/(dt) = (d[NH_(3)])/(dt) xx ("Total wt of" H_(2) "in kg")/("Total wt of" NH_(3) "in kg")`
`= 0.001 kh hr^(-1) xx (3 xx 3 xx 10^(-3))/(2 xx 17 xx 10^(-3))`
`= 1.765 xx 10^(-4) kg hr^(-1)`