While studying the decompoistion of gaseous `N_(2)O_(5)`, it is observed that a plot of logarithm of its partial pressure versus time is linear. What kinetic parameters can be obtained form this observation?

Answer

First order reaction

Explanation

While studying the decompoistion of gaseous `N_(2)O_(5)`, it is observed that a plot of logarithm of its partial pressure versus time is linear. This shows that the decompoistion of `N_(2)O_(5)` follows first order kinetics.
`k = (2.303)/(t) log.(A_(0))/(A_(t))`, or `k = (2.303)/(t) log.(a)/(a-x)`
where `A_(0)` is the initial concentration of the reactants and `A_(t)` is the concentration of the reactants after time `t`. Therefore,
`log A_(t) = log A_(0) - (k)/(2.303)t` , `[[y = mx+c],["Equation of straight line"],["where m = slope"=(-k)/(2.303)],["Integrcept" (c ) = log A_(0)]]`

For the given case, the graph is between logarithm of partial pressure and time. form the slope of the graph, rate constant for the reaction can be calculated.