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2X(g) rarr 3Y(g)+2Z(g) {:("Time (in mi...

`2X(g) rarr 3Y(g)+2Z(g)`
`{:("Time (in min)",0,100,200,):}`
`|{:("Partial pressure of X (mm Hg)",800,400,200,),("Assuming ideal gas condition, calculate",,,,):}|`
(a) Order of reaction
(b) Rate constant
( c) Time taken for `75%` completion of reaction
(d) Total pressure when `p_(x) = 700 mm`

Text Solution

Verified by Experts

The correct Answer is:
(a) `OR = 1`
(b) `k = 6.93 xx 10^(-3) min^(-1)`
(c ) `t_(75%) = 200 min`
(d) `P_("total") = 950 mm Hg`

a. `800overset(100 min)rarr400overset(100 min)rarr200`
Tha half life is constant, therefore, it must be a first order reaction.
b. Half life `= 100 min`
For a first order reaction, rate constant
`k=(0.693)/(100)= 6.93xx10^(-3) min`
c.The time required for the completion of `75%` of the reaction is equal to two half lives.
Therefore, it is `200 min`.
`{:(,2X(g) rarr,3Y(g),+,2Z(g)),("Initial",800,0,,0),("Final",(800-x),(3)/(2)x,,x):}`
`:. (800-x)=700`
or `x=100`
`underset(700)(2X(g))rarrunderset(150)(3Y(g))+underset(100)(2Z(g))`
Total pressure `= 700+150+100= 950 mm Hg`
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