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.(92)U^(238) emits 8 alpha- particles an...

`._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus is

A

`(62)/(41)`

B

`(60)/(41)`

C

`(61)/(42)`

D

`(62)/(42)`

Text Solution

Verified by Experts

The correct Answer is:
A
`8 alpha-` particle emission decreases the atomic mass number by `8xx4=32`. Thereofre ,a atomic mass number of product nucleus is `238-32=206`.
`6 beta-` particles and `8 alpha-` particles emission decreases the atomic number of by `8xx2-6xx1=10`. Therefore, atomic number of product nucleus `=92-10=82`.
`:. ` number of neutrons in nucleus `=206-82=124`.
`:. (n)/(0)=(cancel(124)^(2))/(cancel(82)^(2))=(62)/(41)`
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