If `._(92)U^(235)` assumed to decay only by emitting two `alpha`-and one `beta`-particles, the possible product of decays is

Options

A. `._(89)Ac^(231)`
B. `._(89)Ac^(235)`
C. `._(89)Ac^(236)`
D. `._(89)Ac^(227)`

Answer

D

Explanation

`._(92)U^(235) rarr ._(Z)X^(A) + 2 ._(2)He^(4) + ._(-1)e^(0)`
Equating mass number of both sides
`235 = A + 2 xx 4 + 0`
`:. A = 235 - 8 = 227`
Similarly, equating atomic number of both sides
`92 = Z + 2 xx 2 - 1`
`:. Z = 92 - 3 = 89`
`:. ._(Z)X^(A) = ._(89)Ac^(227)`