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.(13)Al^(27) is a stable isotope. .(13)A...

`._(13)Al^(27)` is a stable isotope. `._(13)Al^(29)` is expected to disintegrate by

A

`alph-` emission

B

`beta-` emission

C

Positron emission

D

Proton emission

Text Solution

Verified by Experts

The correct Answer is:
B
The species `._(13)Al^(29)(` number of neutrons `=16)` contains more neutrons than the stable isotope `._(13)Al^(27)(` number of neutrons `=14)`. Neutrons on decomposition show `beta-` emission.
`._(0)n^(1)rarr._(1)H^(1)+ underset(beta-particl e)(._(-1)e^(0) `
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