In an isoceles triangle OAB , O is the origin and OA=OB=6 . The equation of the side AB is x-y+1=0 Then the area of the triangle is

In the isosceles triangle OAB, O is the origin, OA=OB=6 . If the equation of side AB is x-y+1=0 , then the area of the triangle OAB is (in square units)

The ends of the base of an isoceles triangle are at (2a, 0) and (0, a). The equation of one side is x=2a . The equation of the other side is

Triangle OAB is isosceles right triangle right angled at O.O is origin and equation of AB is 2x+3y=6 then area of triangle OAB is (36)/(13) b.(12)/(17) c.(13)/(5) d.(17)/(13)

The line x+y=a meets the axes of x and y at A and B respectively. A triangle AMN is inscribed in the triangle OAB , O being the origin, with right angle at N, M and N lie respectively on OB and AB. If the area of the triangle AMN is 3/8 of the area of the triangle OAB , then (AN)/(BM) is equal to:

The line x + y = p meets the axis of x and y at A and B respectively. A triangle APQ is inscribed in the triangle OAB, O being the origin, with right angle at Q, P and Q lie respectively on OB and AB. If the area of the triangle APQ is 3//8^(th) of the area of the triangle OAB, then (AQ)/(BQ) is equal to

Delta OAB is formed by the lines x^(2)-4xy+y^(2)=0 and the line AB.The equation of line AB is 2x+3y-1=0 .Find the equation of the median of the triangle drawn from the origin.

(1)A triangle formed by the lines x+y=0 , x-y=0 and lx+my=1. If land m vary subject to the condition l^2+m^2=1 then the locus of the circumcentre of triangle is: (2)The line x +y= p meets the x-axis and y-axis at A and B, respectively. A triangle APQ is inscribed in triangle OAB, O being the origin, with right angle at Q. P and Q lie, respectively, on OB and AB. If the area of triangle APQ is 3/8th of the area of triangle OAB, then (AQ)/(BQ) is: equal to

The line x+y=p meets the x-and y-axes at A and B, respectively. A triangle APQ is inscribed in triangle OAB, O being with right at Q.P and Q lie, respectivley, on OB and AB. If the area of triangle APQ is 3//8 th of the area of triangle OAB, then AQ/BQ is equal to