A force F is related to the position of a particle by the relation `F=(10x^(2))N` . Find the work done by the force when the particle moves from `x=2m to x=4m`.

Force acting on a particle varies with displacement as shown is Fig. Find the work done by this force on the particle from x=-4 m to x = + 4m. .

Force acting on a particle varies with displacement as shown is Fig. Find the work done by this force on the particle from x=-4 m to x = + 4m. .

A particle starts from rest from origin and moves along a parabolic path whose equation is y=x^(2) in the presence of a number of forces.One of the forces acting on the particle is F=(xhat i-4zhat k)N .Find work done by this force F when the particle moves from origin to x=2m.

A block is constrained to move along x axis under a force F=-(2x)N . Find the work done by the force when the block is displaced from x=2 m to x = 4m

A force F acting on a particle varies with the position x as shown in the graph. Find the work done by the force in displacing the particle from x =-a to x = +2a . .

Force acting on a particle varies with x as shown in figure. Calculate the work done by the force as the particle moves from x = 0 to x = 6.0 m.

The force on a particle is directed along an x axis and given by F= F_(0) (x//x_(0)-1) . Find the work done by the force in moving the particle from x=0 to x= 2x_(0) by (a) plotting F(x) and measuring the work from the graph and (b) integrating F(x) .

A force F acting on a particle varies with the position x as shown in figure. Find the work done by this force in displacing the particle from