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" 35."{1+(1)/(1+(1)/(1+(1)/(3)))}-:1(4)/...

" 35."{1+(1)/(1+(1)/(1+(1)/(3)))}-:1(4)/(7)=?

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[1+(1)/(1+(1)/(1+(1)/(3)))]-:1(4)/(7) is equal to (a) 1 (b) 1(1)/(3)( c) 1(1)/(4) (d) 1(1)/(7)

1-(5)/(7+(1)/(4+(1)/(2+(1)/(3))))

Find the sum of the series to n terms and to infinity : (1)/(1.3)+ (1)/(3.5) +(1)/(5.7) +(1)/(7.9)+...

The sum of the first 35 terms of the series (1)/(2) + (1)/(3) -(1)/(4) -(1)/(2) -(1)/(3) +(1)/(4) +(1)/(2) + (1)/(3) -(1)/(4)

(1)/(1.3)+(1)/(2)((1)/(3.5))+(1)/(3)((1)/(5.7))+....=

{:("Quantity A","Quantity B"),((1)/(3)+(1)/(4)+(7)/(12),(1)/((1)/(3)+(1)/(4)+(7)/(12))):}

(3)/(4)" of "((1)/(3)+(1)/(2))-:((1)/(7)+1(1)/(14))" of "2times(1)/(4)-(1)/(2)" of "(3)/(4)

The sum of the first 35 terms of the series (1)/(2)+(1)/(3)-(1)/(4)-(1)/(2)-(1)/(3)+(1)/(4)+(1)/(2)+(1)/(3)-(1)/(4) is -(1)/(2)(b)-(1)/(4) (c) (1)/(4) (e) None of these