A radiation of energy `E` falls normally on a perfctly refelecting surface . The momentum transferred to the surface is

Options

A. `(2E)/(C )`
B. `(2E)/(C ^(2) )`
C. `(E )/(C ^(2))`
D. `(E )/(C ) `

Answer

A

Explanation

E = energy radiated .
Force F `=(dp) /( dt) =("power ")/( "Velocity ") =(dE//dt)/(C ) `
`Delta P =(2E ) /(C ) `