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A cell is connected between the points A and C of a circular conductor ABCD of centre `'O'.angle AOC = 60^(@)`. If` B_(​1) and B_(​2)` are the magnitudes of the magnetic fields at O due to the currents in ABC and ADC respectively, the ratio `(B_(1))/(B_(2))`, is

A

6

B

1

C

5

D

`1//5`

Text Solution

Verified by Experts

The correct Answer is:
B
` B_(1) = (mu _(0) I_(1) alpha _(1))/( 4pi R) B_(2) =(mu _(0) I_(2) alpha _(2) )/( 4 pi R ) `
` :' I_(1) alpha _(1) = I_(2) alpha _(2) `
` so (B_(1))/(B_(2))=1 `
`B_(1) (mu _(0) I_(1) alpha _(1)) ( 4pi R) B_(2) =(mu_(0) I_(2) alpha_(2) )/( 4piR ) `
` I_(2) alpha _(1) =- I_(2) alpha _(2)`
` so (B_(1))/(B_(2))=1 `
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