A proton and and `alpha `- particle are accelerated through a potential difference of `100 V`. The ratio of the wavelength with the proton to that associated to that associated with an `alpha` - particle is

Options

A. `sqrt(2):1`
B. `2:(1)/(sqrt(2))`
C. `2:1`
D. `(1)/(2sqrt(2)):1`

Answer

C

Explanation

`lambda =(h)/(p) =(h)/( sqrt(mqv))`
For same potential difference
`lambda alpha (1)/(sqrt(mq))=(lambda_(p))/(lambda_(r )) = sqrt( (m_(r)q_(r))/(m_(p)q_(p)))=2sqrt(2)`