The perio of oscillation of a magnet in vibration magnetometer is 2 sec. The period of oscillation of a magnet whosr magnetic moment is four times that of the first magnet is

Options

A. 8s
B. 4s
C. 1s
D. 0.5 s

Answer

C

Explanation

The tme period
`T=2pi sqrt(I//MB_(H))`
Thus `(T_(2))/(T_(1)) = sqrt((M_(1))/(M_(2)))=sqrt((1)/(4)) =(1)/(2)`
`or T_(2) = 2 xx I//2`
= 1 sec the answer is (3) 1 sec