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20% radioactive sample decay in time t....

`20%` radioactive sample decay in time t. How much sample decay in time 2t ?

A

`40%`

B

`36%`

C

`44%`

D

`80%`

Text Solution

Verified by Experts

The correct Answer is:
B
`20%` decay in timet
means `80%` remaining , `(N)/(N_(0))= (80)/(100) =(8)/(10)`
In time `2t ((N)/(N_(0))) = ((80)/(100))^(2) = .64`
`rArr 64%` remaining means `36%` deecay.
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