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A gas 'X' is dissolved in water at 2 bar...

A gas 'X' is dissolved in water at 2 bar pressure. Its mole fraction is `0.02` in solution. The mole fraction of water when the pressure of gas is doubled at the same temperature is :

A

0.04

B

0.98

C

0.96

D

0.02

Text Solution

Verified by Experts

The correct Answer is:
C
`p=K_(H)x`
`2=K_(H)xx0.02" …(i)"`
`4=K_(H)xx x" …(ii)"`
From eqs. (i) and (ii).
`(1)/(2)=(0.02)/(x)`
`x=0.04`
Mole fraction of water `=1-0.04=0.96`
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