Assign `E-Z` configuration to each of the following:
a.

Explanation

a. `(Z)` Priority of `HC-=C- gt CMe_(3)` and priority of `CH_(2)=CH- gt -CHMe_(2)`, So two higher priority groups on same side, hence `Z`-configuration.
b. `(E )` priority of `-CH_(2)Cl gt Me` and `CH_(3) CH_(2)-gt Me`. So two higher priority groups on opposite sides, hence `E-`configuration.
(c ). `(E )` Priority of `I gt CH_(2)OH` and `-CHMe_(2) gt CH_(3)CH_(2)CH_(2)-`. So two higher priority groups on opposite sides, hence `E`-configuration.
(d) `(E )` Priority of `Br gt COOH` and `CH_(3)CH_(2)-gt H`. So two higher priority groups on opposite sides, hence `E`-configuration.