a. The specific rotation of a pure enantiomer is `+10^(@)`. What will be its observed rotation if its is isolated from a reaction with i. `30%` racemisation and `70%` retention. ii. `70%` racemisation and `30%` inversion. b. What is the percentage composition of a mixtrue of two enantiomers whose rotation is `-10^(@)`? The specific rotation of pure enantiomers is `-20^(@)`. c. What is the optical purity of a sample having an `[alpha]_(obs.)=+9.0^(@)` if `[alpha]_(D)=+12^(@)`.
Text Solution
Verified by Experts
a. i. `[alpha]_(obs.)= 0.70xx(+10^(@))= +7.0^(@)` ii. `30%` inversion, with inversion specific rotation is `(-10^(@))`. `:. [alpha]_(obs.)=0.30 xx (-10^(@)) = -3.0^(@)` b. Optical purity `(OP)` of sample `=([alpha]_(obs.))/([alpha]_(D))` `= (-10^(@)xx100)/(-20^(@))=50%` So, `50%` of the mixtrue consists of `(-)` enantiomer and `50%` is the racemate [i.e., `25% (+)` and `25%(-)` form] Total percentage of `(-)` form `= 50%+25%=75%` Total percentage of `(+)` form `=25%` c. Optical purity `(OP)` of sample `=(+9^(@))/(+12^(@))xx100= 75%` The mixtrue has `75% (+)` and `25%` racemic mixtrue [i.e., `12.5%(+)` and `12.5%(-)` form] Total percentage of `(+)` form `=75%+(25%)/(2)= 87.5%` Total percentage of `(-)` form `=12.5%`
CENGAGE CHEMISTRY|Exercise Chemical Equilibrium|72 Videos
Similar Questions
Explore conceptually related problems
The specific rotation of a pure enantiomers is +12^(@) . What will be its observed rotation if it is isolated form a reaction with 20% racemization and 80% retention.
The specific rotation of a pure enantiomers is +12^(@) . What will be its observed rotation if it is isolated form a reaction with 80% racemization and 20% inversion.
The specific rotation of a pure enantiomer is +10^(@) . The observed rotation, if it is isolated from a reaction with 30% recemisation and 70% inversion is
The specific rotation of a pure enantiomer is +16^(@) its observed rotation if it is isolated from a reaction with 25% racemisation and 75% retention is,
The specific rotation of a pure enantiomer is +16^@ . The observed rotation, if it is isolated from a reaction with 25% racemisation and 75% inversion is
A and B are enantiomer of each other. Specific rotation of A is 20^(@) .Rotation of mixture of A and B =-5^(@) what is the percentage of recemic part ?
What is the number whose 20% is 30% of 40 ?
A and B are enantiomer to each other . If specific rotation of A is + 20^(@) rotaion of mix of A and B is -10^(@) then find the percentage of A and B in the mixture ?
(+) mandelic acid has a specific rotation of 158^(@) What would be the observed specific rotation of a mixture of 25% (-) mandelic acid and 75% (+) mandelic acid ?
A partially racemised (+) - 2-bromo-octane (2^@ RX) on reaction with aq. NaOH in acetone gives an alcohol with 80 % inversion and 20 % racemisation. What is the percentage of back-side attack ?
CENGAGE CHEMISTRY-ISOMERISM-Assertion-Reasoning Type