Home
Class 11
PHYSICS
A bullet of mass 10 g moving horizontall...

A bullet of mass 10 g moving horizontally at asped dof `50sqrt7m/s` strikes a block of mass 490 g kept on a frictionless track as shown in figure. The bullet remains inside the block and the system proceeds towards the semicircular tract o radius 0.2 m. Where will the block strike the horizontal part after leaving the semicircular track?

Promotional Banner

Similar Questions

Explore conceptually related problems

A bullet of mass 10g moving horizontally at a speed of 50 7 ​ m/s strikes a block of mass 490g kept on a frictionless track as shown in figure. The bullet. remains inside the block and the system proceeds towards the semicircular track of radius 0.2m. Where will the block strike the horizontal part after leaving the semicircular track?

A bullet of mass 10 kg moving horizontally at a speed 140 m//s strikes a block of mass 100 g attached to a string like a simple pendulum. The bullet penetrates the block and emerges on the other side. If the block rises by 80 cm , find final velocity of bullet.

A bullet of mass 10 g moving with a speed of 20 m/s hits an ice block of mass 990 g kept on a frictionless floor and gets stuck in it. How much ice will melt if 50\% of the lost KE goes to ice? (initial temperature of the ice block and bullet = 0^(@)C )

A bullet of mass 10 g moving horizontally with a speed of 400 m//s a block of mass 390 g and remains in it. The block slides 10 m on rough surface before coming to rest. The friction coefficient is

A bullet of mass 20 g moving horizontally at a speed of 300 m/s is fired into a wooden block of mass 500 g suspended by a long string. The bullet crosses the block and emerges on the other side. If the centre of mass of the block rises through a height of 20.0 cm, find the speed of the bullet as it emerges from the block.

A bullet of mass 10 g travelling horizontally with a velocity of 150 m s^-1 strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the force exerted by the wooden block

A mass of 10 g moving horizontally with a velocity of 100 m/s, strikes a pendulum bob of mass 10 y. The two masses strike together. The maximum height reached by the system now is g = 10 m//s) :

A bullet of mass 10 g travelling horizontally with a velocity of 150 m s^-1 strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block.

A bullet of mass 10 g travelling horizontally with a velocity of 300 m/s strikes a block of wood of mass 290 g which rests on a rough horizontal floor. After impact the block and the bullet move together and come to rest when the block has travelled a distance of 15 m. The coefficient of friction between the block and the floor will be - (Duration of impact is very short)

A bullet of mass 0.01 kg travelling at a speed of 500 m/s strikes a block of mass 2 kg, which is suspended by a string of length 5 m. The centre of gravity of the block is found to rise a vertical distance of 0.1 m. The speed of the bullet after it emerges from the block will be -