The rate constant for the decomposition of hydrocarbons is `2.418xx10^(-5)s^(-1)` at `546K`. If the energy of activation is `179.9kJ mol^(-1)`, what will be the value of pre`-`exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418 xx 10^(-5) "s"^(-1) at 546 K. If the energy of activation is 179.9" kJ mol"^(-1) , what will be the value of pre-exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418xx10^(-5)s^(-1) as 546 K . If the energy of activation is 179.9 kJ.mol , what will be the value of pre-exponential factor ?

The rate constant for the decomposition of hydrocarbons is 2.418 xx 10^(-5)s^(-1) at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.

The rate constant for the decomposition of a hydrocarbon is 2.418xx10^-5 s^-1 at 546 K. If the energy of activation is 179.9 KJ mol^-1 , What will be the value of pre-exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418xx10^(-5)s^(-1) at 546K. If the energy of activation is 179.9kJ//mol what will be the value of pre-exponantial factor?